Cisco CCNP Certifications Exam 642-892

The output if this program is 6 5. To understand why, we look first at the simpler situation of 'i', 642-642 and we see why a five is printed for it, and then next at the more complicated situation with 'j' and why a six is printed for it.

A new variable 'i' is created at each new level of scope. Thus only the first assignment to 'i', where 'i' is assigned the value of five, affects this particular variable 'i': the 642-825 variable that is printed. That variable does not alter its value after that first assignment and so the final statement prints a five. The other assignments to 'i' are irrelevant to the final print statement.

In contrast, the variable 'j' is created only once, hence the assignment where `j' is assigned the value of six, alters this only existing variable called 'j' even though the variable is 642-892 declared at an enclosing level of scope. If a program has a scope level inside another, and no variable of the right name is declared at this inner level, then the computer `looks outwards' to the next enclosing level of scope.